等差數列前n項立方和公式?a(n)=a(1)+(n-1)d[a(n)]^3=[a(1)+(n-1)d]^3=[a(1)]^3+3(n-1)d[a(1)]^2+3(n-1)^2d^2 a(1)+(n-1)^3d^3，我來為大家講解一下關于等差數列前n項立方和公式?跟着小編一起來看一看吧!
a(n)=a(1)+(n-1)d
[a(n)]^3=[a(1)+(n-1)d]^3=[a(1)]^3+3(n-1)d[a(1)]^2+3(n-1)^2d^2 a(1)+(n-1)^3d^3
[a[1]]^3+a[2]^3+...........+a[n]^3
=n[a(1)]^3
+3d[a(1)]^2 [0+1+2+.......(n-1)]
+3d^2 a(1) [0^2+1^2+...........+(n-1)^2]
+d^3 [0^3+1^3+........+(n-1)^3]
=n[a(1)]^3+3d[a[1]]^2 n(n-1)/2+ n[a(1)]^3*(n-1)n(2n-1)/2+d^3*n^2(n-1)^2/4
更多精彩资讯请关注tft每日頭條，我们将持续为您更新最新资讯!
zpostcode 
Recruit 
weather 
mreligion 
Yellowpages 
sport 
constellation 
shopping 
name 
game 
directory 
literature 
Word 
tour 
furnish 
Lottery 
tftnews 
lyrics 
News 
digital 
car 
dir 
Edu 
Finance 
