兩點經緯度計算兩點間距離實例?public class DecimalFormatUtil {
//地球平均半徑
private static final double EARTH_RADIUS = 6378.137;
//把經緯度轉為度（°）
private static double rad(double d) {
return d * Math.PI / 180.0;
}
/**
* 通過經緯度獲取距離(單位：)
* ulongitude 用戶所在 -- 經度
* ulatitude 用戶所在 -- 緯度
* latitude 發布等 -- 緯度
* longitude 發布等 -- 經度
* @return 距離
*/
public static double getDistance(double ulongitude, double longitude,double ulatitude, double latitude) {
double radLat1 = rad(ulongitude);
double radLat2 = rad(longitude);
double a = radLat1 - radLat2;
double b = rad(ulatitude) - rad(latitude);
double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2)));
s = s * EARTH_RADIUS;
s = s / 1000;
DecimalFormat df = new DecimalFormat("#.00");
s = Double.parseDouble(df.format(s));
return s;
}
public static void main(String[] args) {
double distance1 = getDistance(104.046115, 30.6030110000, 104.074666, 30.611842);
System.out.println("Distance is: " distance1 " km");
}
}，我來為大家科普一下關于兩點經緯度計算兩點間距離實例?以下内容希望對你有幫助!
public class DecimalFormatUtil {
//地球平均半徑
private static final double EARTH_RADIUS = 6378.137;
//把經緯度轉為度（°）
private static double rad(double d) {
return d * Math.PI / 180.0;
}
/**
* 通過經緯度獲取距離(單位：)
* ulongitude 用戶所在 -- 經度
* ulatitude 用戶所在 -- 緯度
* latitude 發布等 -- 緯度
* longitude 發布等 -- 經度
* @return 距離
*/
public static double getDistance(double ulongitude, double longitude,double ulatitude, double latitude) {
double radLat1 = rad(ulongitude);
double radLat2 = rad(longitude);
double a = radLat1 - radLat2;
double b = rad(ulatitude) - rad(latitude);
double s = 2 * Math.asin(Math.sqrt(Math.pow(Math.sin(a / 2), 2) Math.cos(radLat1) * Math.cos(radLat2) * Math.pow(Math.sin(b / 2), 2)));
s = s * EARTH_RADIUS;
s = s / 1000;
DecimalFormat df = new DecimalFormat("#.00");
s = Double.parseDouble(df.format(s));
return s;
}
public static void main(String[] args) {
double distance1 = getDistance(104.046115, 30.6030110000, 104.074666, 30.611842);
System.out.println("Distance is: " distance1 " km");
}
}
SELECT
title,
longitude,
latitude,
ROUND(
6378.138 * 2 * ASIN(
SQRT(
POW(
SIN(
(
30.611842 * PI() / 180 - latitude * PI() / 180
) / 2
),
2
) COS(30.611842 * PI() / 180) * COS(latitude * PI() / 180) * POW(
SIN(
(
104.074666 * PI() / 180 - longitude * PI() / 180
) / 2
),
2
)
)
) * 1000
) AS distance_um
FROM
mac_rent_in
ORDER BY
distance_um ASC
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