（一）程序代碼：
#include<iostream>
#include<cmath>
#define N 100
using namespace std;
int main()
{
system("title 計算定積分");
double a=0,b=1,x,h,F=0;
h=(b-a)/N;
x=(h-a)/2;
while(x<=b)
{
F=F exp(x)*h;
x=x h;
}
cout<<"e^x從"<<a<<"到"<<b<<"的定積分："<<F<<endl;
return 0;
}
（二）程序運行結果：
（三）函數exp(x)從0到1定積分的幾何意義
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